x=16x^2+150x+1

Solution for x=16x^2+150x+1 equation:

x=16x^2+150x+1

We move all terms to the left:

x-(16x^2+150x+1)=0

We get rid of parentheses

-16x^2+x-150x-1=0

We add all the numbers together, and all the variables

-16x^2-149x-1=0

a = -16; b = -149; c = -1;
Δ = b2-4ac
Δ = -1492-4·(-16)·(-1)
Δ = 22137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-149)-\sqrt{22137}}{2*-16}=\frac{149-\sqrt{22137}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-149)+\sqrt{22137}}{2*-16}=\frac{149+\sqrt{22137}}{-32}
$